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%2B\arctan(x)=\frac{%CF%80}{4}&line2=\mathrm{Solution:\:}x=\frac{\sqrt{17}-3}{4} "arctan(2x)+arctan(x)= pi/4")
arctan(2x)+arctan(x)= pi/4
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File:Mplwp arcsin arccos arctan piaxis.svg - Wikimedia Commons
![A Surprising Identity! [ arctan(x)+arctan(1/x)=pi/2 ] - YouTube](https://i.ytimg.com/vi/UuY4pAml510/maxresdefault.jpg "A Surprising Identity! [ arctan(x)+arctan(1/x)=pi/2 ] - YouTube")
A Surprising Identity! [ arctan(x)+arctan(1/x)=pi/2 ] - YouTube
&line2=\mathrm{Solution:\:}-\arctan(\frac{%CF%80}{36}) "arctan(-pi/(36))")
arctan(-pi/(36))
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Picture proof of arctan(1) + arctan(2) + arctan(3) = pi. : r/math
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![SOLVED: 6.4.b.11) Calculating Look at this info: Tan[Pi/6] This tells you that 6 ArcTan[ =T N[Pi, 10] 3 . 141592654 Take your answer; p[x]: to part i) and evaluate NPl/5] 1o] In](https://cdn.numerade.com/ask_images/7fedf92cc5d7467da2d547e927880449.jpg "SOLVED: 6.4.b.11) Calculating Look at this info: Tan[Pi/6] This tells you that 6 ArcTan[ =T N[Pi, 10] 3 . 141592654 Take your answer; p[x]: to part i) and evaluate NPl/5] 1o] In")
SOLVED: 6.4.b.11) Calculating Look at this info: Tan[Pi/6] This tells you that 6 ArcTan[ =T N[Pi, 10] 3 . 141592654 Take your answer; p[x]: to part i) and evaluate NPl/5] 1o] In
